(2X+15)+(3x-20)x=(x+15)

Solution for (2X+15)+(3x-20)x=(x+15) equation:

(2X+15)+(3X-20)X=(X+15)

We move all terms to the left:

(2X+15)+(3X-20)X-((X+15))=0

We multiply parentheses

3X^2+(2X+15)-20X-((X+15))=0

We get rid of parentheses

3X^2+2X-20X-((X+15))+15=0


We calculate terms in parentheses: -((X+15)), so:

(X+15)

We get rid of parentheses

X+15

Back to the equation:

-(X+15)


We add all the numbers together, and all the variables

3X^2-18X-(X+15)+15=0

We get rid of parentheses

3X^2-18X-X-15+15=0

We add all the numbers together, and all the variables

3X^2-19X=0

a = 3; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·3·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*3}=\frac{0}{6}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*3}=\frac{38}{6}
=6+1/3
$