(2x+15)+(3x-20)+x=(x+15)

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Solution for (2x+15)+(3x-20)+x=(x+15) equation: 



(2x+15)+(3x-20)+x=(x+15)

We move all terms to the left:

(2x+15)+(3x-20)+x-((x+15))=0

We add all the numbers together, and all the variables

x+(2x+15)+(3x-20)-((x+15))=0

We get rid of parentheses

x+2x+3x-((x+15))+15-20=0



We calculate terms in parentheses: -((x+15)), so:

(x+15)

We get rid of parentheses

x+15

Back to the equation:

-(x+15)



We add all the numbers together, and all the variables

6x-(x+15)-5=0

We get rid of parentheses

6x-x-15-5=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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