(2x+13)=(6x-8)+(4x+19)

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Solution for (2x+13)=(6x-8)+(4x+19) equation: 



(2x+13)=(6x-8)+(4x+19)

We move all terms to the left:

(2x+13)-((6x-8)+(4x+19))=0

We get rid of parentheses

2x-((6x-8)+(4x+19))+13=0



We calculate terms in parentheses: -((6x-8)+(4x+19)), so:

(6x-8)+(4x+19)

We get rid of parentheses

6x+4x-8+19

We add all the numbers together, and all the variables

10x+11

Back to the equation:

-(10x+11)



We get rid of parentheses

2x-10x-11+13=0

We add all the numbers together, and all the variables

-8x+2=0

We move all terms containing x to the left, all other terms to the right

-8x=-2

x=-2/-8

x=1/4

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