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(3x+11)+(7x-18)=(x+4)
We move all terms to the left:
(3x+11)+(7x-18)-((x+4))=0
We get rid of parentheses
3x+7x-((x+4))+11-18=0
We calculate terms in parentheses: -((x+4)), so:We add all the numbers together, and all the variables
(x+4)
We get rid of parentheses
x+4
Back to the equation:
-(x+4)
10x-(x+4)-7=0
We get rid of parentheses
10x-x-4-7=0
We add all the numbers together, and all the variables
9x-11=0
We move all terms containing x to the left, all other terms to the right
9x=11
x=11/9
x=1+2/9
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