(3x+11)+(x+4)=(7x-18)

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Solution for (3x+11)+(x+4)=(7x-18) equation: 



(3x+11)+(x+4)=(7x-18)

We move all terms to the left:

(3x+11)+(x+4)-((7x-18))=0

We get rid of parentheses

3x+x-((7x-18))+11+4=0



We calculate terms in parentheses: -((7x-18)), so:

(7x-18)

We get rid of parentheses

7x-18

Back to the equation:

-(7x-18)



We add all the numbers together, and all the variables

4x-(7x-18)+15=0

We get rid of parentheses

4x-7x+18+15=0

We add all the numbers together, and all the variables

-3x+33=0

We move all terms containing x to the left, all other terms to the right

-3x=-33

x=-33/-3

x=+11

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