(2x+13)=(3x+20)+(7x+7)

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Solution for (2x+13)=(3x+20)+(7x+7) equation: 



(2x+13)=(3x+20)+(7x+7)

We move all terms to the left:

(2x+13)-((3x+20)+(7x+7))=0

We get rid of parentheses

2x-((3x+20)+(7x+7))+13=0



We calculate terms in parentheses: -((3x+20)+(7x+7)), so:

(3x+20)+(7x+7)

We get rid of parentheses

3x+7x+20+7

We add all the numbers together, and all the variables

10x+27

Back to the equation:

-(10x+27)



We get rid of parentheses

2x-10x-27+13=0

We add all the numbers together, and all the variables

-8x-14=0

We move all terms containing x to the left, all other terms to the right

-8x=14

x=14/-8

x=-1+3/4

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