(2x+6)=(3x+4)+(9x-18)

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Solution for (2x+6)=(3x+4)+(9x-18) equation: 



(2x+6)=(3x+4)+(9x-18)

We move all terms to the left:

(2x+6)-((3x+4)+(9x-18))=0

We get rid of parentheses

2x-((3x+4)+(9x-18))+6=0



We calculate terms in parentheses: -((3x+4)+(9x-18)), so:

(3x+4)+(9x-18)

We get rid of parentheses

3x+9x+4-18

We add all the numbers together, and all the variables

12x-14

Back to the equation:

-(12x-14)



We get rid of parentheses

2x-12x+14+6=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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