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(2x+13)(3x+9)=0
We multiply parentheses ..
(+6x^2+18x+39x+117)=0
We get rid of parentheses
6x^2+18x+39x+117=0
We add all the numbers together, and all the variables
6x^2+57x+117=0
a = 6; b = 57; c = +117;
Δ = b2-4ac
Δ = 572-4·6·117
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-21}{2*6}=\frac{-78}{12} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+21}{2*6}=\frac{-36}{12} =-3 $
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