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(x-11)(x-10)=0
We multiply parentheses ..
(+x^2-10x-11x+110)=0
We get rid of parentheses
x^2-10x-11x+110=0
We add all the numbers together, and all the variables
x^2-21x+110=0
a = 1; b = -21; c = +110;
Δ = b2-4ac
Δ = -212-4·1·110
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-1}{2*1}=\frac{20}{2} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+1}{2*1}=\frac{22}{2} =11 $
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