3x(2x+2)+27x(x+1)-36=0

Solution for 3x(2x+2)+27x(x+1)-36=0 equation:

3x(2x+2)+27x(x+1)-36=0

We multiply parentheses

6x^2+27x^2+6x+27x-36=0

We add all the numbers together, and all the variables

33x^2+33x-36=0

a = 33; b = 33; c = -36;
Δ = b2-4ac
Δ = 332-4·33·(-36)
Δ = 5841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5841}=\sqrt{9*649}=\sqrt{9}*\sqrt{649}=3\sqrt{649}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-3\sqrt{649}}{2*33}=\frac{-33-3\sqrt{649}}{66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+3\sqrt{649}}{2*33}=\frac{-33+3\sqrt{649}}{66}
$