(2x+12)+(x+36)+((1/6)x+56)=180

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Solution for (2x+12)+(x+36)+((1/6)x+56)=180 equation: 



(2x+12)+(x+36)+((1/6)x+56)=180

We move all terms to the left:

(2x+12)+(x+36)+((1/6)x+56)-(180)=0



Domain of the equation: 6)x+56)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(2x+12)+(x+36)+((+1/6)x+56)-180=0

We get rid of parentheses

2x+x+((+1/6)x+56)+12+36-180=0

We multiply all the terms by the denominator


2x*6)x+56)+x*6)x+56)+((+1+12*6)x+56)+36*6)x+56)-180*6)x+56)=0

We add all the numbers together, and all the variables

2x*6)x+56)+x*6)x+56)+(73x+56)+36*6)x+56)-180*6)x+56)=0

Wy multiply elements

2592x^5=0

We do not support expression: x^5

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