(4a+2)(3-2a)=0

Solution for (4a+2)(3-2a)=0 equation:

(4a+2)(3-2a)=0

We add all the numbers together, and all the variables

(4a+2)(-2a+3)=0

We multiply parentheses ..

(-8a^2+12a-4a+6)=0

We get rid of parentheses

-8a^2+12a-4a+6=0

We add all the numbers together, and all the variables

-8a^2+8a+6=0

a = -8; b = 8; c = +6;
Δ = b2-4ac
Δ = 82-4·(-8)·6
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*-8}=\frac{-24}{-16}
=1+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*-8}=\frac{8}{-16}
=-1/2
$