(2x+10)(5x+11)=0

Solution for (2x+10)(5x+11)=0 equation:

(2x+10)(5x+11)=0

We multiply parentheses ..

(+10x^2+22x+50x+110)=0

We get rid of parentheses

10x^2+22x+50x+110=0

We add all the numbers together, and all the variables

10x^2+72x+110=0

a = 10; b = 72; c = +110;
Δ = b2-4ac
Δ = 722-4·10·110
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-28}{2*10}=\frac{-100}{20}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+28}{2*10}=\frac{-44}{20}
=-2+1/5
$