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4(2x-3)-3x=13+5(x+-3)
We move all terms to the left:
4(2x-3)-3x-(13+5(x+-3))=0
We add all the numbers together, and all the variables
4(2x-3)-3x-(13+5(x-3))=0
We add all the numbers together, and all the variables
-3x+4(2x-3)-(13+5(x-3))=0
We multiply parentheses
-3x+8x-(13+5(x-3))-12=0
We calculate terms in parentheses: -(13+5(x-3)), so:We add all the numbers together, and all the variables
13+5(x-3)
determiningTheFunctionDomain 5(x-3)+13
We multiply parentheses
5x-15+13
We add all the numbers together, and all the variables
5x-2
Back to the equation:
-(5x-2)
5x-(5x-2)-12=0
We get rid of parentheses
5x-5x+2-12=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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