-(1/9)(x-27)+(1/3)(x+3)=x+4

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Solution for -(1/9)(x-27)+(1/3)(x+3)=x+4 equation: 



-(1/9)(x-27)+(1/3)(x+3)=x+4

We move all terms to the left:

-(1/9)(x-27)+(1/3)(x+3)-(x+4)=0



Domain of the equation: 9)(x-27)!=0

x∈R





Domain of the equation: 3)(x+3)!=0

x∈R



We add all the numbers together, and all the variables

-(+1/9)(x-27)+(+1/3)(x+3)-(x+4)=0

We get rid of parentheses

-(+1/9)(x-27)+(+1/3)(x+3)-x-4=0

We multiply parentheses ..

-(+x^2+1/9*-27)+(+1/3)(x+3)-x-4=0

We calculate fractions

There is no solution for this equation

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