4(2x-3)-3x=13+5(x+-0)

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Solution for 4(2x-3)-3x=13+5(x+-0) equation: 



4(2x-3)-3x=13+5(x+-0)

We move all terms to the left:

4(2x-3)-3x-(13+5(x+-0))=0

We add all the numbers together, and all the variables

4(2x-3)-3x-(13+5(+x))=0

We add all the numbers together, and all the variables

-3x+4(2x-3)-(13+5(+x))=0

We multiply parentheses

-3x+8x-(13+5(+x))-12=0



We calculate terms in parentheses: -(13+5(+x)), so:

13+5(+x)

determiningTheFunctionDomain
5(+x)+13

We multiply parentheses

5x+13

Back to the equation:

-(5x+13)



We add all the numbers together, and all the variables

5x-(5x+13)-12=0

We get rid of parentheses

5x-5x-13-12=0

We add all the numbers together, and all the variables

-25!=0

There is no solution for this equation

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