(2x+1)/20=8x+5

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Solution for (2x+1)/20=8x+5 equation:



(2x+1)/20=8x+5
We move all terms to the left:
(2x+1)/20-(8x+5)=0
We get rid of parentheses
(2x+1)/20-8x-5=0
We multiply all the terms by the denominator
(2x+1)-8x*20-5*20=0
We add all the numbers together, and all the variables
(2x+1)-8x*20-100=0
Wy multiply elements
(2x+1)-160x-100=0
We get rid of parentheses
2x-160x+1-100=0
We add all the numbers together, and all the variables
-158x-99=0
We move all terms containing x to the left, all other terms to the right
-158x=99
x=99/-158
x=-99/158

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