(2x+3)(x)=230

Solution for (2x+3)(x)=230 equation:

(2x+3)(x)=230

We move all terms to the left:

(2x+3)(x)-(230)=0

We multiply parentheses

2x^2+3x-230=0

a = 2; b = 3; c = -230;
Δ = b2-4ac
Δ = 32-4·2·(-230)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-43}{2*2}=\frac{-46}{4}
=-11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+43}{2*2}=\frac{40}{4}
=10
$