m2+21m+20=0

Solution for m2+21m+20=0 equation:

m2+21m+20=0

We add all the numbers together, and all the variables

m^2+21m+20=0

a = 1; b = 21; c = +20;
Δ = b2-4ac
Δ = 212-4·1·20
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-19}{2*1}=\frac{-40}{2}
=-20
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+19}{2*1}=\frac{-2}{2}
=-1
$