(2x+-8)(x+8)=0

Solution for (2x+-8)(x+8)=0 equation:

(2x+-8)(x+8)=0

We add all the numbers together, and all the variables

(2x-8)(x+8)=0

We multiply parentheses ..

(+2x^2+16x-8x-64)=0

We get rid of parentheses

2x^2+16x-8x-64=0

We add all the numbers together, and all the variables

2x^2+8x-64=0

a = 2; b = 8; c = -64;
Δ = b2-4ac
Δ = 82-4·2·(-64)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*2}=\frac{16}{4}
=4
$