6(1+3r)=2(10r+9)-4r

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Solution for 6(1+3r)=2(10r+9)-4r equation: 



6(1+3r)=2(10r+9)-4r

We move all terms to the left:

6(1+3r)-(2(10r+9)-4r)=0

We add all the numbers together, and all the variables

6(3r+1)-(2(10r+9)-4r)=0

We multiply parentheses

18r-(2(10r+9)-4r)+6=0



We calculate terms in parentheses: -(2(10r+9)-4r), so:

2(10r+9)-4r

We add all the numbers together, and all the variables

-4r+2(10r+9)

We multiply parentheses

-4r+20r+18

We add all the numbers together, and all the variables

16r+18

Back to the equation:

-(16r+18)



We get rid of parentheses

18r-16r-18+6=0

We add all the numbers together, and all the variables

2r-12=0

We move all terms containing r to the left, all other terms to the right

2r=12

r=12/2

r=6

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