3(y+4)=5(y-3)+24

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Solution for 3(y+4)=5(y-3)+24 equation:



3(y+4)=5(y-3)+24
We move all terms to the left:
3(y+4)-(5(y-3)+24)=0
We multiply parentheses
3y-(5(y-3)+24)+12=0
We calculate terms in parentheses: -(5(y-3)+24), so:
5(y-3)+24
We multiply parentheses
5y-15+24
We add all the numbers together, and all the variables
5y+9
Back to the equation:
-(5y+9)
We get rid of parentheses
3y-5y-9+12=0
We add all the numbers together, and all the variables
-2y+3=0
We move all terms containing y to the left, all other terms to the right
-2y=-3
y=-3/-2
y=1+1/2

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