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(2x)2=676
We move all terms to the left:
(2x)2-(676)=0
We add all the numbers together, and all the variables
2x^2-676=0
a = 2; b = 0; c = -676;
Δ = b2-4ac
Δ = 02-4·2·(-676)
Δ = 5408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5408}=\sqrt{2704*2}=\sqrt{2704}*\sqrt{2}=52\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52\sqrt{2}}{2*2}=\frac{0-52\sqrt{2}}{4} =-\frac{52\sqrt{2}}{4} =-13\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52\sqrt{2}}{2*2}=\frac{0+52\sqrt{2}}{4} =\frac{52\sqrt{2}}{4} =13\sqrt{2} $
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