(2w-3)w=30

Solution for (2w-3)w=30 equation:

(2w-3)w=30

We move all terms to the left:

(2w-3)w-(30)=0

We multiply parentheses

2w^2-3w-30=0

a = 2; b = -3; c = -30;
Δ = b2-4ac
Δ = -32-4·2·(-30)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{249}}{2*2}=\frac{3-\sqrt{249}}{4}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{249}}{2*2}=\frac{3+\sqrt{249}}{4}
$