(x+3)/4=(x-4)/6

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Solution for (x+3)/4=(x-4)/6 equation:



(x+3)/4=(x-4)/6
We move all terms to the left:
(x+3)/4-((x-4)/6)=0
We calculate fractions
x/()+(-((x-4)*4)/()=0
We calculate terms in parentheses: +(-((x-4)*4)/(), so:
-((x-4)*4)/(
We multiply all the terms by the denominator
-((x-4)*4)
We calculate terms in parentheses: -((x-4)*4), so:
(x-4)*4
We multiply parentheses
4x-16
Back to the equation:
-(4x-16)
We get rid of parentheses
-4x+16
Back to the equation:
+(-4x+16)
We get rid of parentheses
x/()-4x+16=0
We multiply all the terms by the denominator
x-4x*()+16*()=0
We add all the numbers together, and all the variables
x-4x*()=0

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