8(z+6)=7(z-3)+z

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Solution for 8(z+6)=7(z-3)+z equation: 



8(z+6)=7(z-3)+z

We move all terms to the left:

8(z+6)-(7(z-3)+z)=0

We multiply parentheses

8z-(7(z-3)+z)+48=0



We calculate terms in parentheses: -(7(z-3)+z), so:

7(z-3)+z

We add all the numbers together, and all the variables

z+7(z-3)

We multiply parentheses

z+7z-21

We add all the numbers together, and all the variables

8z-21

Back to the equation:

-(8z-21)



We get rid of parentheses

8z-8z+21+48=0

We add all the numbers together, and all the variables

69!=0

There is no solution for this equation

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