(2n+4)+(3n-19)=100

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Solution for (2n+4)+(3n-19)=100 equation: 



(2n+4)+(3n-19)=100

We move all terms to the left:

(2n+4)+(3n-19)-(100)=0

We get rid of parentheses

2n+3n+4-19-100=0

We add all the numbers together, and all the variables

5n-115=0

We move all terms containing n to the left, all other terms to the right

5n=115

n=115/5

n=23

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