3/5(2x+4)+2(x+2)=16

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Solution for 3/5(2x+4)+2(x+2)=16 equation: 



3/5(2x+4)+2(x+2)=16

We move all terms to the left:

3/5(2x+4)+2(x+2)-(16)=0



Domain of the equation: 5(2x+4)!=0

x∈R



We multiply parentheses

3/5(2x+4)+2x+4-16=0

We multiply all the terms by the denominator


2x*5(2x+4)+4*5(2x+4)-16*5(2x+4)+3=0

Wy multiply elements

10x^2(2+20x(2-80x(2+3=0

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