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3x-1=5(x-1)+2(2-x)
We move all terms to the left:
3x-1-(5(x-1)+2(2-x))=0
We add all the numbers together, and all the variables
3x-(5(x-1)+2(-1x+2))-1=0
We calculate terms in parentheses: -(5(x-1)+2(-1x+2)), so:We get rid of parentheses
5(x-1)+2(-1x+2)
We multiply parentheses
5x-2x-5+4
We add all the numbers together, and all the variables
3x-1
Back to the equation:
-(3x-1)
3x-3x+1-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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