8(n-1)=4(n+2)

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Solution for 8(n-1)=4(n+2) equation: 



8(n-1)=4(n+2)

We move all terms to the left:

8(n-1)-(4(n+2))=0

We multiply parentheses

8n-(4(n+2))-8=0



We calculate terms in parentheses: -(4(n+2)), so:

4(n+2)

We multiply parentheses

4n+8

Back to the equation:

-(4n+8)



We get rid of parentheses

8n-4n-8-8=0

We add all the numbers together, and all the variables

4n-16=0

We move all terms containing n to the left, all other terms to the right

4n=16

n=16/4

n=4

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