(20-4x)+3x=28

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Solution for (20-4x)+3x=28 equation: 



(20-4x)+3x=28

We move all terms to the left:

(20-4x)+3x-(28)=0

We add all the numbers together, and all the variables

(-4x+20)+3x-28=0

We add all the numbers together, and all the variables

3x+(-4x+20)-28=0

We get rid of parentheses

3x-4x+20-28=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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