(2n+1)(8n+1)=0

Solution for (2n+1)(8n+1)=0 equation:

(2n+1)(8n+1)=0

We multiply parentheses ..

(+16n^2+2n+8n+1)=0

We get rid of parentheses

16n^2+2n+8n+1=0

We add all the numbers together, and all the variables

16n^2+10n+1=0

a = 16; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·16·1
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6}{2*16}=\frac{-16}{32}
=-1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6}{2*16}=\frac{-4}{32}
=-1/8
$