0.5(2x-1)=(1/3)(2x+0.5)

Solution for 0.5(2x-1)=(1/3)(2x+0.5) equation:

0.5(2x-1)=(1/3)(2x+0.5)

We move all terms to the left:

0.5(2x-1)-((1/3)(2x+0.5))=0


Domain of the equation: 3)(2x+0.5))!=0

x∈R


We add all the numbers together, and all the variables

0.5(2x-1)-((+1/3)(2x+0.5))=0

We multiply parentheses

x-((+1/3)(2x+0.5))-0.5=0

We multiply parentheses ..

-((+2x^2+1/3*0.5))+x-0.5=0

We multiply all the terms by the denominator


-((+2x^2+1+x*3*0.5))-(0.5)*3*0.5))=0


We calculate terms in parentheses: -((+2x^2+1+x*3*0.5)), so:

(+2x^2+1+x*3*0.5)

We get rid of parentheses

2x^2+x*3*0.5+1

Wy multiply elements

2x^2+1.5x+1

Back to the equation:

-(2x^2+1.5x+1)


We add all the numbers together, and all the variables

-(2x^2+1.5x+1)=0

We get rid of parentheses

-2x^2-1.5x-1=0

a = -2; b = -1.5; c = -1;
Δ = b2-4ac
Δ = -1.52-4·(-2)·(-1)
Δ = -5.75
Delta is less than zero, so there is no solution for the equation