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-5x+200=-31/3x+150
We move all terms to the left:
-5x+200-(-31/3x+150)=0
Domain of the equation: 3x+150)!=0We get rid of parentheses
x∈R
-5x+31/3x-150+200=0
We multiply all the terms by the denominator
-5x*3x-150*3x+200*3x+31=0
Wy multiply elements
-15x^2-450x+600x+31=0
We add all the numbers together, and all the variables
-15x^2+150x+31=0
a = -15; b = 150; c = +31;
Δ = b2-4ac
Δ = 1502-4·(-15)·31
Δ = 24360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24360}=\sqrt{4*6090}=\sqrt{4}*\sqrt{6090}=2\sqrt{6090}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{6090}}{2*-15}=\frac{-150-2\sqrt{6090}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{6090}}{2*-15}=\frac{-150+2\sqrt{6090}}{-30} $
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