(2m-1)(m+3)=3

Solution for (2m-1)(m+3)=3 equation:

(2m-1)(m+3)=3

We move all terms to the left:

(2m-1)(m+3)-(3)=0

We multiply parentheses ..

(+2m^2+6m-1m-3)-3=0

We get rid of parentheses

2m^2+6m-1m-3-3=0

We add all the numbers together, and all the variables

2m^2+5m-6=0

a = 2; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·2·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*2}=\frac{-5-\sqrt{73}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*2}=\frac{-5+\sqrt{73}}{4}
$