2/5x+x=35

Solution for 2/5x+x=35 equation:

2/5x+x=35

We move all terms to the left:

2/5x+x-(35)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

x+2/5x-35=0

We multiply all the terms by the denominator


x*5x-35*5x+2=0

Wy multiply elements

5x^2-175x+2=0

a = 5; b = -175; c = +2;
Δ = b2-4ac
Δ = -1752-4·5·2
Δ = 30585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-175)-\sqrt{30585}}{2*5}=\frac{175-\sqrt{30585}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-175)+\sqrt{30585}}{2*5}=\frac{175+\sqrt{30585}}{10}
$