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8p-4/3p=2
We move all terms to the left:
8p-4/3p-(2)=0
Domain of the equation: 3p!=0We multiply all the terms by the denominator
p!=0/3
p!=0
p∈R
8p*3p-2*3p-4=0
Wy multiply elements
24p^2-6p-4=0
a = 24; b = -6; c = -4;
Δ = b2-4ac
Δ = -62-4·24·(-4)
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{105}}{2*24}=\frac{6-2\sqrt{105}}{48} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{105}}{2*24}=\frac{6+2\sqrt{105}}{48} $
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