(2c-9)/7=8-c

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Solution for (2c-9)/7=8-c equation: 



(2c-9)/7=8-c

We move all terms to the left:

(2c-9)/7-(8-c)=0

We add all the numbers together, and all the variables

(2c-9)/7-(-1c+8)=0

We get rid of parentheses

(2c-9)/7+1c-8=0

We multiply all the terms by the denominator


(2c-9)+1c*7-8*7=0

We add all the numbers together, and all the variables

(2c-9)+1c*7-56=0

Wy multiply elements

(2c-9)+7c-56=0

We get rid of parentheses

2c+7c-9-56=0

We add all the numbers together, and all the variables

9c-65=0

We move all terms containing c to the left, all other terms to the right

9c=65

c=65/9

c=7+2/9

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