5(x+2)-4=7(2x-5)-13

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Solution for 5(x+2)-4=7(2x-5)-13 equation: 



5(x+2)-4=7(2x-5)-13

We move all terms to the left:

5(x+2)-4-(7(2x-5)-13)=0

We multiply parentheses

5x-(7(2x-5)-13)+10-4=0



We calculate terms in parentheses: -(7(2x-5)-13), so:

7(2x-5)-13

We multiply parentheses

14x-35-13

We add all the numbers together, and all the variables

14x-48

Back to the equation:

-(14x-48)



We add all the numbers together, and all the variables

5x-(14x-48)+6=0

We get rid of parentheses

5x-14x+48+6=0

We add all the numbers together, and all the variables

-9x+54=0

We move all terms containing x to the left, all other terms to the right

-9x=-54

x=-54/-9

x=+6

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