(2c+12)(12-2c)=0

Solution for (2c+12)(12-2c)=0 equation:

(2c+12)(12-2c)=0

We add all the numbers together, and all the variables

(2c+12)(-2c+12)=0

We multiply parentheses ..

(-4c^2+24c-24c+144)=0

We get rid of parentheses

-4c^2+24c-24c+144=0

We add all the numbers together, and all the variables

-4c^2+144=0

a = -4; b = 0; c = +144;
Δ = b2-4ac
Δ = 02-4·(-4)·144
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-4}=\frac{-48}{-8}
=+6
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-4}=\frac{48}{-8}
=-6
$