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(28+2x)(10+2x)=1144
We move all terms to the left:
(28+2x)(10+2x)-(1144)=0
We add all the numbers together, and all the variables
(2x+28)(2x+10)-1144=0
We multiply parentheses ..
(+4x^2+20x+56x+280)-1144=0
We get rid of parentheses
4x^2+20x+56x+280-1144=0
We add all the numbers together, and all the variables
4x^2+76x-864=0
a = 4; b = 76; c = -864;
Δ = b2-4ac
Δ = 762-4·4·(-864)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-140}{2*4}=\frac{-216}{8} =-27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+140}{2*4}=\frac{64}{8} =8 $
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