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3(2x-4)=6+6x-18
We move all terms to the left:
3(2x-4)-(6+6x-18)=0
We add all the numbers together, and all the variables
3(2x-4)-(6x-12)=0
We multiply parentheses
6x-(6x-12)-12=0
We get rid of parentheses
6x-6x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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