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7(x+4)=2(3x+14)+x
We move all terms to the left:
7(x+4)-(2(3x+14)+x)=0
We multiply parentheses
7x-(2(3x+14)+x)+28=0
We calculate terms in parentheses: -(2(3x+14)+x), so:We get rid of parentheses
2(3x+14)+x
We add all the numbers together, and all the variables
x+2(3x+14)
We multiply parentheses
x+6x+28
We add all the numbers together, and all the variables
7x+28
Back to the equation:
-(7x+28)
7x-7x-28+28=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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