(24y-18/2y)+(5/y)=13

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Solution for (24y-18/2y)+(5/y)=13 equation: 



(24y-18/2y)+(5/y)=13

We move all terms to the left:

(24y-18/2y)+(5/y)-(13)=0



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R





Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+24y-18/2y)+(+5/y)-13=0

We get rid of parentheses

24y-18/2y+5/y-13=0

We calculate fractions


24y+(-18y)/2y^2+10y/2y^2-13=0

We multiply all the terms by the denominator


24y*2y^2+(-18y)+10y-13*2y^2=0

We add all the numbers together, and all the variables

10y+24y*2y^2+(-18y)-13*2y^2=0

Wy multiply elements

48y^3-26y^2+10y+(-18y)=0

We get rid of parentheses

48y^3-26y^2+10y-18y=0

We do not support eypression: y^3

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