(2p+1)7=64p+12/6

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Solution for (2p+1)7=64p+12/6 equation: 



(2p+1)7=64p+12/6

We move all terms to the left:

(2p+1)7-(64p+12/6)=0

We add all the numbers together, and all the variables

(2p+1)7-(64p+2)=0

We multiply parentheses

14p-(64p+2)+7=0

We get rid of parentheses

14p-64p-2+7=0

We add all the numbers together, and all the variables

-50p+5=0

We move all terms containing p to the left, all other terms to the right

-50p=-5

p=-5/-50

p=1/10

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