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5+4(5x-4)-2(x+3)=10(3x-1)+5
We move all terms to the left:
5+4(5x-4)-2(x+3)-(10(3x-1)+5)=0
We multiply parentheses
20x-2x-(10(3x-1)+5)-16-6+5=0
We calculate terms in parentheses: -(10(3x-1)+5), so:We add all the numbers together, and all the variables
10(3x-1)+5
We multiply parentheses
30x-10+5
We add all the numbers together, and all the variables
30x-5
Back to the equation:
-(30x-5)
18x-(30x-5)-17=0
We get rid of parentheses
18x-30x+5-17=0
We add all the numbers together, and all the variables
-12x-12=0
We move all terms containing x to the left, all other terms to the right
-12x=12
x=12/-12
x=-1
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