(21x+25)+((675x-27)/3)=180

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Solution for (21x+25)+((675x-27)/3)=180 equation: 



(21x+25)+((675x-27)/3)=180

We move all terms to the left:

(21x+25)+((675x-27)/3)-(180)=0

We get rid of parentheses

21x+((675x-27)/3)+25-180=0

We multiply all the terms by the denominator


21x*3)+((675x-27)+25*3)-180*3)=0

We add all the numbers together, and all the variables

21x*3)+((675x-27)=0

Wy multiply elements

63x^2=0

a = 63; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·63·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{126}=0$

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