(3x)=(4x+19)

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Solution for (3x)=(4x+19) equation: 



(3x)=(4x+19)

We move all terms to the left:

(3x)-((4x+19))=0



We calculate terms in parentheses: -((4x+19)), so:

(4x+19)

We get rid of parentheses

4x+19

Back to the equation:

-(4x+19)



We get rid of parentheses

3x-4x-19=0

We add all the numbers together, and all the variables

-1x-19=0

We move all terms containing x to the left, all other terms to the right

-x=19

x=19/-1

x=-19

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