(21b-2)-5(4b+3)=-7

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Solution for (21b-2)-5(4b+3)=-7 equation: 



(21b-2)-5(4b+3)=-7

We move all terms to the left:

(21b-2)-5(4b+3)-(-7)=0

We add all the numbers together, and all the variables

(21b-2)-5(4b+3)+7=0

We multiply parentheses

(21b-2)-20b-15+7=0

We get rid of parentheses

21b-20b-2-15+7=0

We add all the numbers together, and all the variables

b-10=0

We move all terms containing b to the left, all other terms to the right

b=10

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