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1/3w-5=4/5w
We move all terms to the left:
1/3w-5-(4/5w)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: 5w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
1/3w-(+4/5w)-5=0
We get rid of parentheses
1/3w-4/5w-5=0
We calculate fractions
5w/15w^2+(-12w)/15w^2-5=0
We multiply all the terms by the denominator
5w+(-12w)-5*15w^2=0
Wy multiply elements
-75w^2+5w+(-12w)=0
We get rid of parentheses
-75w^2+5w-12w=0
We add all the numbers together, and all the variables
-75w^2-7w=0
a = -75; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-75)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-75}=\frac{0}{-150} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-75}=\frac{14}{-150} =-7/75 $
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